Home Physics Work, Energy, Power and Collision Conservation of Energy and Momentum In gravity-free space, a man of mass M stand…
Physics Work, Energy, Power and Collision Conservation of Energy and Momentum MCQ (Single Correct)

In gravity-free space, a man of mass M standing at a height h above the floor throws a ball of mass m straight down with a speed u. When the ball reaches the floor, the distance of the man above the floor will be -

A
h
B
h
C
2h
D
A function of m, M, h and u

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Text Solution

Verified by Experts
The correct answer is:
A

Due to conservation of momentum in the vertical direction, the man will begin to move up with speed . The ball will reach the floor in time . In this time the man will move up by . Total distance of man from floor = h + .

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